108k views
2 votes
Critical pints of f in Let f(x)=x3+27x+4

1 Answer

7 votes

Answer:

Critical points: none

Explanation:

We are given the function;

f(x)=x³+27x+4

We are required to determine the critical points

First we can find the derivative of the function;


f(x)=x^3+27x+4

Thus, the derivative will be;


f'(x)=3x^2+27

But, at critical point the derivative is equal to zero or undefined

Therefore;


3x^2+27=0\\3x^2=-27\\x^2=-9\\

Thus, the function has no critical points

User Cbr
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories