Question

Critical pints of f in Let f(x)=x3+27x+4

Answer 1

Critical points: none

Explanation:

We are given the function;

f(x)=x³+27x+4

We are required to determine the critical points

First we can find the derivative of the function;

`f(x)=x^3+27x+4`

Thus, the derivative will be;

`f'(x)=3x^2+27`

But, at critical point the derivative is equal to zero or undefined

Therefore;

`3x^2+27=0\\3x^2=-27\\x^2=-9\\`

Thus, the function has no critical points