The total surface area is given by:
- The base of the cylinder
- The lateral surface of the cylinder
- The surface of the hemishpere
The base of the cylinder is a circle with radius 5cm, so its area is
![A=\pi r^2=25\pi](https://img.qammunity.org/2021/formulas/mathematics/middle-school/eof2dp9856im6pv4olezvqo0kzmxly0py0.png)
The lateral surface of the cylinder is a rectangle whose base is the circumference of the base circle, and whose height is the height of the cylinder. So, its area is
![A=b\cdot h=2\pi r\cdot h = 10\pi\cdot 8=80\pi](https://img.qammunity.org/2021/formulas/mathematics/middle-school/95xv9v5mrwldb8dusuvzyjj37f1kl02tzc.png)
Finally, the surface of a sphere is given by
![A=4\pi r^2](https://img.qammunity.org/2021/formulas/physics/high-school/ps6viya84klv6cy9rkdj3mls0rvqdqk2cq.png)
so, half that surface will be
![A=2\pi r^2=50\pi](https://img.qammunity.org/2021/formulas/mathematics/middle-school/im9qyu6ec9htgie7swyhd3zu5kfvdhvy2r.png)
And the total surface area will be the sum of the three areas:
![A=25\pi+80\pi+50\pi = 155\pi](https://img.qammunity.org/2021/formulas/mathematics/middle-school/a44ar5gswb52cwzz6cdnlftf1f4b6zhu5a.png)