156k views
4 votes
5) through (-2, -3) and (0,1)
Slope-Intercept:
Standard Form: ​

2 Answers

5 votes

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:


y = mx + b

Where:

m: It is the slope of the line

b: It is the cut point with the y axis

We have the following points:


(x_ {1}, y_ {1}): (0,1)\\(x_ {2}, y_ {2}): (-2, -3)

We find the slope:
m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-3-1} {- 2-0} = \frac {-4} {- 2} = 2

Thus, the equation is of the form:


y = 2x + b

We substitute a point and find b:


1 = 2 (0) + b\\b = 1

Finally, we have:


y = 2x + 1

On the other hand, the equation in the standard form is given by:


ax + by = c

So, according to the slope-intersection equation we have:


2x-y = -1

Answer:


y=2x+1\\2x-y=-1

User Cmt
by
8.5k points
1 vote

Answer:

Slope = 2

y-intercept = 1

x-intercept = -0.5

Standard Form ⇒ y - 2x = 1

Explanation:

write the equation of the line through (-2 , -3) and (0,1)

The general form of the line is y = mx + c

Where m is the slope and c is the y-intercept

The slope m = (y₂ - y₁)/(x₂ - x₁) = (1 - [-3])/(0 - [-2]) = 4/2 = 2

∴ y = 2x + c

By substitution with the point (0,1) to find c

1 = 2 *0 + c

c = 1

∴ y = 2x + 1

Or y - 2x = 1 ⇒Standard Form

Also,

See the attached figure which represents the graph of the line y - 2x = 1

5) through (-2, -3) and (0,1) Slope-Intercept: Standard Form: ​-example-1
User Conf
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories