Question

Where is the removable discontinuity of f(x) located?
x = -5
F(x)=5x+10/x^2+7x+10

Answer 1

The discontinuity of f(x) is at x=25. The denominator goes to zero.

Answer 2

F(x)=0

Explanation:

5x+10/x^2+7x+10

When x=-5

Substitute the value of x in the equation

5(-5)+10/(-5^2+7(-5)+10

-25+10/25-35+10

-15/-10+10

-15/0

=0