Answer:
A) P(E | F) = 0.817
B) P(F | E) = 0.613
Explanation:
From the question,
P(E) = 0.8, P(F) = 0.6
P(E∩F) = 0.49
A) From conditional probability;
P(E | F) = [P(E∩F)]/P(F) = 0.49/0.6 = 0.8167 which is approximately 0.817 in 3 decimal places.
B) Also, P(F | E) = [P(F∩E)]/P(E) = 0.49/0.8 = 0.6125 which is approximately 0.613 in 3 decimal places.