The probability of selecting a random student who is enrolled in both the courses is 0.280.
Explanation:
Here, the total number of freshman in the university = 500
The number of students enrolled in Economics = n(E) = 323
The number of students enrolled in Mathematics = n(M) = 205
The number of students enrolled in Both Economics and math
= n(E∩M ) = 140
Let F : Event of selecting a student who is enrolled in both the courses
So, from the given data:
![P(F) = \frac{\textrm{Total number of favorable outcomes}}{\textrm{Total number of outcomes}} \\= \frac{\textrm{Total number of students enrolled in BOTH courses}}{\textrm{Total number of students}} \\ = (140)/(500) = (7)/(25)](https://img.qammunity.org/2021/formulas/mathematics/high-school/g626t0bbefl4s4sn64bhpr0un7qbsoepwe.png)
So, the probability of selecting a random students who is enrolled in both the courses is
![((7)/(25) ) = 0.280](https://img.qammunity.org/2021/formulas/mathematics/high-school/sjoreqc16vtfrwphvneezghsn9s6g72nuj.png)