Answer:
Step-by-step explanation:
First we calculate the energy of the photon
E=(Planck constant × speed of light in vacuum)÷ wave length
E=
![(6.626*10^(34)*2.998*10^(8) )/(638*10^(-9) ) = 3.114*10^(49)](https://img.qammunity.org/2021/formulas/physics/college/bkzpy0y1oy0kt723d6y03k47r9tpme43u1.png)
Next we find the total energy per second
total energy=
![1*10^(-3)W *(1JS^(-1) )/(1W) = 1*10^(-3) JS^(-1)](https://img.qammunity.org/2021/formulas/physics/college/93qf8b2yvagb15c9upvicckovm5ka034c5.png)
Next we calculate the number the photon per second
= total energy ÷ energy of 1 photon
=
![(1*10^(-3) JS^(-1) )/(3.114*10^(49) ) = 3.21*10^(-53) \ photons/sec](https://img.qammunity.org/2021/formulas/physics/college/64kpo0xrl75z7e9jri88ob6lhyk7qz3ern.png)