Question

Consider a 2.54-cm-diameter power line for which the potential difference from the ground, 19.6 m below, to the power line is 115 kV. Find the line charge density on the power line. Wolfson, Richard. Essential University Physics, Volume 2 (p. 431). Pearson Education. Kindle Edition.

Answer 1

The line charge density is
`1.59*10^(-4)\ C/m`

Step-by-step explanation:

Given that,

Diameter = 2.54 cm

Distance = 19.6 m

Potential difference = 115 kV

We need to calculate the line charge density

Using formula of potential difference

`V=EA`

`V=(\lambda)/(2\pi\epsilon_(0)r)*\pi r^2`

`\lambda=(V*2\epsilon_(0))/(r)`

Where, r = radius

V = potential difference

Put the value into the formula

`\lambda=(115*10^(3)*2*8.8*10^(-12))/(1.27*10^(-2))`

`\lambda=1.59*10^(-4)\ C/m`

Hence, The line charge density is
`1.59*10^(-4)\ C/m`