Question

The ventilating fan of the bathroom has a volumetric flow rate of 1,901 L/s. If the air density is 1.23 kg/m3, calculate the mass flow rate of air in kg/h

Answer 1

`\dot m_(air) = 8417.628\,(kg)/(h)`

Step-by-step explanation:

Mass flow rate of air is:

`\dot m _(air) = \rho_(air)\cdot \dot V_(fan)`

`\dot m_(air) = (1.23\,(kg)/(m^(3)))\cdot (1901\,(L)/(s) )\cdot ((1\,m^(3))/(1000\,L) )\cdot ((3600\,s)/(1\,h) )`

`\dot m_(air) = 8417.628\,(kg)/(h)`