Question

At which temperature would a reaction with AH = -220 kJ/mol and

AS=-0.05 kJ/(mol-K) be spontaneous?

Answer 1

3600 K

Step-by-step explanation:

i just took the test on a pex :)

Answer 2

• C. 3600K

Step-by-step explanation:

The condition for a reaction to be spontaneous is that the change if the free energy, ΔG, be negative.

The definition of G is G = H - TS, from which, at constant temperature:

• ΔG = ΔH - TΔS

Thus, you must solve:

• ΔG = ΔH - TΔS < 0

Substituting:

• -220kJ/mol - T(-0.05kJ/mol) < 0

• -220kJ/mol + T(0.05kJ/mol) < 0

• T < -220kJ/mol / ( 0.05kJ/mol)

• T < 4,400K

The only choice with a temperature less than 4,400K is C. 3600K.