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You plan to install an active, liquid-based solar heating system for hot water. There are four candidate collector systems. Your calculations provided the following data for the month of June. Using f-charts/equations, which of the four collector systems will provide the most collected energy for the month? X Y2.87 0.963.466 0.9983.229 1.085.525 1.0094

1 Answer

5 votes

Solution:

The given formula,


x=F_(R) U_(L) * (P l)/(F R_(1)) *\left(T_(r e f)-\bar{T}_(a)\right) \Delta t * (A_(c))/(L)


y=F_(R)(\tau \alpha)_(n) x (F_(R)^(\prime))/(F_(R)) * \frac{(\bar{\tau} d)}{(T d)_(n)} * \bar{H}_(T) N * (A C)/(L)


(x)/(y)=\frac{ u_(L) *\left(T_(x t)-\bar{T}_(a)\right) * \Delta t}{\left(\tau_(x)\right)_(h) *\left(\frac{\bar{\tau}_(d)}\left.\right) * \bar{H}+N}

From the table,


1) \(\quad x=2 \cdot 87, \quad y=0.96\)\\\((x)/(y)=(2187)/(0.96)\)22895\\\\2) \(x=3 \cdot 466 \cdot y=6 \cdot 998\)\\\((x)/(y)=(3 \cdot 466)/(0.898)\)\(=3 \cdot 4729\)


3\(x=3 \cdot 229, y=1 \cdot 08\)\\\((x)/(x)=(3 \cdot 229)/(1 \cdot 08)\)\\=2.9898\)\\\\4) \(x=6.525, y=1.094\)\\\((x)/(y)=(5.625)/(1.094)\)\\=5.0502

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