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What are the diameters of the painting?
Easy!!!

What are the diameters of the painting? Easy!!!-example-1

1 Answer

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x = 10.22 in

Solution:

Width of the figure = x in

Length of the figure = (2x + 5) in

Area of the figure = 260 in²

To find the value of x:

Area of the figure = length × width

length × width = 260

(2x + 5) × x = 260


2x^2+5x=260

Subtract 260 from both sides of the equation.


2x^2+5x-260=0

Factor the above quadratic expression.

Quadratic equation formula:


$x=\frac{-b \pm \sqrt{b^(2)-4 a c}}{2 a}


$x=\frac{-5 \pm \sqrt{5^(2)-4 \cdot 2(-260)}}{2 \cdot 2}


$x=(-5 \pm √(2105))/(4)


$x=(-5+√(2105))/(4), \ x=(-5-√(2105))/(4)

x = 10.22, x = –12.72006

Dimension of the figure cannot be measured in negative terms.

Hence x = 10.22 in.

User Marcmagransdeabril
by
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