Question

Problem PageQuestion Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 8.42 g of ethane is mixed with 48. g of oxygen. Calculate the minimum mass of ethane that could be left over by the chemical reaction. Round your answer to significant digits.

Answer 1

No ethane will be left after reaction

Step-by-step explanation:

Balanced equation:
`2C_(2)H_(6)+7O_(2)\rightarrow 4CO_(2)+6H_(2)O`

According to balanced equation, 7 moles of
`O_(2)` react completely with 2 moles of
`C_(2)H_(6)`

Molar mass of
`O_(2)` = 32 g/mol and molar mass of ethane = 30.07 g/mol

So, 48 g of
`O_(2)` =
`(48)/(32)mol` of
`O_(2)` = 1.5 moles of
`O_(2)`

Hence, 1.5 moles of
`O_(2)` react completely with
`((2)/(7)* 1.5)` moles of
`C_(2)H_(6)` or 0.43 moles of
`C_(2)H_(6)`

So, mass of
`C_(2)H_(6)` reacts completely with 1.5 moles of
`O_(2)` =
`(0.43* 30.07)g` = 12.9 g

As only 8.42 g of ethane has been placed in reaction mixture therefore no ethane will be left after reaction.