118k views
1 vote
Problem PageQuestion Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 8.42 g of ethane is mixed with 48. g of oxygen. Calculate the minimum mass of ethane that could be left over by the chemical reaction. Round your answer to significant digits.

User Samoth
by
7.8k points

1 Answer

1 vote

Answer:

No ethane will be left after reaction

Step-by-step explanation:

Balanced equation:
2C_(2)H_(6)+7O_(2)\rightarrow 4CO_(2)+6H_(2)O

According to balanced equation, 7 moles of
O_(2) react completely with 2 moles of
C_(2)H_(6)

Molar mass of
O_(2) = 32 g/mol and molar mass of ethane = 30.07 g/mol

So, 48 g of
O_(2) =
(48)/(32)mol of
O_(2) = 1.5 moles of
O_(2)

Hence, 1.5 moles of
O_(2) react completely with
((2)/(7)* 1.5) moles of
C_(2)H_(6) or 0.43 moles of
C_(2)H_(6)

So, mass of
C_(2)H_(6) reacts completely
with 1.5 moles of
O_(2) =
(0.43* 30.07)g = 12.9 g

As only 8.42 g of ethane has been placed in reaction mixture therefore no ethane will be left after reaction.

User Riaj Ferdous
by
8.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.