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If the loop sits in a uniform magnetic field of 3.5~T3.5 T that is oriented in the horizontal +x direction, what is the magnitude of the torque on the wire loop?

User Cephron
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7.8k points

1 Answer

4 votes

Answer:

The magnitude of the torque on the wire loop is 3.68 Nm.

Step-by-step explanation:

Given that,

Magnetic field = 3.5 T

Suppose, A circular wire loop with a radius of 62.7 cm lies flat in the horizontal x-y plane and contains a current of 852 mA that runs counter-clockwise in the wire loop when viewed from above.

We need to calculate the area

Using formula of area


A=\pi r^2

Put the value into the formula


A=\pi*(62.7*10^(-2))^2


A=1.235\ m^2

We need to calculate the magnitude of the torque on the wire loop

Using formula of magnetic field


\tau=NIAB\sin90

Put the value into the formula


\tau=1*852*10^(-3)*1.235*3.5*1


\tau=3.68\ Nm

Hence, The magnitude of the torque on the wire loop is 3.68 Nm.

User AussieJoe
by
8.6k points
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