Question

If the loop sits in a uniform magnetic field of 3.5~T3.5 T that is oriented in the horizontal +x direction, what is the magnitude of the torque on the wire loop?

Answer 1

The magnitude of the torque on the wire loop is 3.68 Nm.

Step-by-step explanation:

Given that,

Magnetic field = 3.5 T

Suppose, A circular wire loop with a radius of 62.7 cm lies flat in the horizontal x-y plane and contains a current of 852 mA that runs counter-clockwise in the wire loop when viewed from above.

We need to calculate the area

Using formula of area

`A=\pi r^2`

Put the value into the formula

`A=\pi*(62.7*10^(-2))^2`

`A=1.235\ m^2`

We need to calculate the magnitude of the torque on the wire loop

Using formula of magnetic field

`\tau=NIAB\sin90`

Put the value into the formula

`\tau=1*852*10^(-3)*1.235*3.5*1`

`\tau=3.68\ Nm`

Hence, The magnitude of the torque on the wire loop is 3.68 Nm.