Answer:
The correct answer is - Homozygous Dominant (R)= 125
Heterozygous (Rr)= 250
Step-by-step explanation:
By the Hardy-Weinberg equation., one can find the value of the recessive, dominant and heterozygous frequency of an individual frequency in a particular frequency. The two important equation are:
p + q = 1 . . . . . . . . (a)
p² + 2pq + q²=1 . . . . . (b)
Where, p² is homozygous dominant character and q² is homozygous recessive character and 2pq is the heterozgous genotype or dominant so,
q² = 25% given so q would be = √25 = 0.5
By equation a p = 1 - 0.5 = 0.5
So the p² would be 25% as well that is = 500×25/100 = 125
2pq =500 - (q²+p²) = 500-(125+125) = 250.
Thus, the correct answer would be = Homozygous Dominant (R)= 125
Heterozygous (Rr)= 250