234k views
5 votes
MAX POINTS help me

The amplitude of this graph is 3 the maximum is 4 the minimum is -2 the period is 4 and the midline is 1 how would the function be written?

MAX POINTS help me The amplitude of this graph is 3 the maximum is 4 the minimum is-example-1
User Timpone
by
8.3k points

2 Answers

7 votes

General equation:-

  • Asin(bx)+c

So

  • Amplitude=A=-3

Min=-2 ,max=4

Hence

  • b=|(mn)|π/mx
  • b=|-2|π/4
  • b=2π/4
  • b=π/2

midline =c=1

So plugin the values

  • y=-3sin(π/2x)+1
User Netwire
by
7.7k points
8 votes


\qquad\qquad\huge\underline{{\sf Answer}}♨

The required equation is :


\qquad \sf  \dashrightarrow \:a \sin(bx) + c

Now, let's find the required values :

period (p) = 4

[distance between any successive Crest or trough]

a = - 3 (flipped)

b = 2π/p = 2π/4 = π/2

k = 1

Distance of starting position from origin = k

Now, plug in the values ~


\qquad \sf  \dashrightarrow \: - 3 \sin( ( \pi)/(2)x ) + 1

User Amit Kaspi
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories