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MAX POINTS help me

The amplitude of this graph is 3 the maximum is 4 the minimum is -2 the period is 4 and the midline is 1 how would the function be written?

MAX POINTS help me The amplitude of this graph is 3 the maximum is 4 the minimum is-example-1
User Timpone
by
3.7k points

2 Answers

7 votes

General equation:-

  • Asin(bx)+c

So

  • Amplitude=A=-3

Min=-2 ,max=4

Hence

  • b=|(mn)|π/mx
  • b=|-2|π/4
  • b=2π/4
  • b=π/2

midline =c=1

So plugin the values

  • y=-3sin(π/2x)+1
User Netwire
by
3.3k points
8 votes


\qquad\qquad\huge\underline{{\sf Answer}}♨

The required equation is :


\qquad \sf  \dashrightarrow \:a \sin(bx) + c

Now, let's find the required values :

period (p) = 4

[distance between any successive Crest or trough]

a = - 3 (flipped)

b = 2π/p = 2π/4 = π/2

k = 1

Distance of starting position from origin = k

Now, plug in the values ~


\qquad \sf  \dashrightarrow \: - 3 \sin( ( \pi)/(2)x ) + 1

User Amit Kaspi
by
3.5k points