Question

Consider the balanced equation. 2HCl + Mg MgCl2 + H2 If 40.0 g of HCl react with an excess of magnesium metal, what is the theoretical yield of hydrogen?

Answer 1

1.11

Step-by-step explanation:

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Answer 2

Theoretical yield of hydrogen is 1.11 g

Step-by-step explanation:

Balanced equation,
`Mg+2HCl\rightarrow MgCl_(2)+H_(2)`

As Mg remain present in excess therefore HCl is the limiting reagent.

According to balanced equation, 2 moles of HCl produce 1 mol of
`H_(2)`.

Molar mass of HCl = 36.46 g/mol

So, 40.0 g of HCl =
`(40.0)/(36.46)moles` of HCl = 1.10 moles of HCl

Hence, theoretically, number of moles of
`H_(2)` are produced from 1.10 moles of HCl =
`((1)/(2)* 1.10)moles=0.550moles`

Molar mass of
`H_(2)` = 2.016 g/mol

So, theoretical yield of
`H_(2)` =
`(0.550* 2.016)g=1.11g`