Answer:
See step by step explanation.
Explanation:
Recall that given two integers a, b, a divides b if there exists an integer k such that b = ka.
Let a,b,d be integers, such that d>0.
a) Suppose that d divides a and d divides b. Then, there exists
such that
and
. Consider a+b and a-b. Replacing the previous equation, we have that
![a+b = k_1 d + k_2 d = (k_1+k_2) d](https://img.qammunity.org/2021/formulas/mathematics/college/nwv4ls63skqxn2li1xo49jbchotupa31gb.png)
![a-b = k_1 d - k_2 d = (k_1-k_2) d](https://img.qammunity.org/2021/formulas/mathematics/college/ixv6znepuvogf3gi7evdi1axftbuna209j.png)
Since
then
and
are both integers. Then, d divides both a+b and a-b.
b) It is false. Let a = 7, b = 5. Then d = 2 divides a+b (12) and a-b (2) but neither 2 divides 7 nor 2 divides 5.