Question

At a bridal store, 73% of customers buy a wedding dress . Only 52% of customers get a wedding dress and get a veil. What is the probability that a customer who gets a wedding dress also gets a veil? Round your answer to the nearest tenth of a percent.

Answer 1

71.2%

Explanation:

The probability of events A and B happening together is

`P(A \:and\: B ) = P(A)*P(B\vert A)`

Now, the event A is costumers buying a wedding dress and its probability is

`P(A)= 73\%`.

And the probability that a costumer gets a wedding dress AND a veil is

`P(A \:and\: B ) = 52\%`

Therefore, the probability
`P(B\vert A)` that a costumer who gets a wedding dress also gets a veil is

`P(B\vert A) = (P(A \:and\: B ))/(P(A)) )`

`P(B\vert A) = (52\% )/(73\%)`

`\boxed{P(B\vert A) = 71.2\%}`