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The Empire State Building is about 381m high. If you threw a baseball downward at 25 m/s from the top of the building how fast would it be traveling just before it landed?
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The Empire State Building is about 381m high. If you threw a baseball downward at 25 m/s from the top of the building how fast would it be traveling just before it landed?

User Jonathan Bechtel
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1 Answer

9 votes

Answer:

Step-by-step explanation:

You can use that
v = v_(o)+gt or
v^(2)=v_(o)^(2)+2gh=(25)^(2)+(2)(10)(381)=8245 \rightarrow v \approx 90.8 m/s.

User Rohan Bhatia
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