Question

The Empire State Building is about 381m high. If you threw a baseball downward at 25 m/s from the top of the building how fast would it be traveling just before it landed?

Answer 1

Step-by-step explanation:

You can use that
`v = v_(o)+gt` or
`v^(2)=v_(o)^(2)+2gh=(25)^(2)+(2)(10)(381)=8245 \rightarrow v \approx 90.8` m/s.