Question

A slab of glass with an index of refraction of 1.65 is submerged in a liquid with an index of refraction of 1.22. Light in the liquid is incident on the glass.

(a) Find the angle of refraction for the angle of incidence of 60°.
°

(b) Find the angle of refraction for the angle of incidence of 45°.
°

(c) Find the angle of refraction for the angle of incidence of 30°.

Answer 1

Step-by-step explanation:

Given that,

Refractive index of glass, n₁ = 1.65

Refractive index of liquid, n₂ = 1.22

(a) We need to find the angle of refraction for the angle of incidence of 60°. It can be calculated using Snells law as :

`n_2\sin i=n_1\sin r`

r is the angle of refraction

`\sin r=(n_2\sin i)/(n_1)`

`\sin r=(1.22\sin (60))/(1.65)`

`r=39.81^(\circ)`

(b)
`n_2\sin i=n_1\sin r`

r is the angle of refraction

Here, i = 45 degrees

`\sin r=(n_2\sin i)/(n_1)`

`\sin r=(1.22\sin (45))/(1.65)`

`r=31.52^(\circ)`

(c)
`n_2\sin i=n_1\sin r`

r is the angle of refraction

Here, i = 30 degrees

`\sin r=(n_2\sin i)/(n_1)`

`\sin r=(1.22\sin (30))/(1.65)`

`r=21.69^(\circ)`

Hence, this is the required solution.