Question

A 2.0 kg lab car moving to the right with an initial velocity of 3.0 m/s collides with a 1.0 kg lab car moving to the left with a velocity of 8.0 m/s in a inelastic collision. What us the final velocity?

Answer 1

Step-by-step explanation:

Check attachment for solution

Answer 2

`v=-0.667\,(m)/(s)`

Step-by-step explanation:

The physical model of a inelastic collision is modelled after the Principle of Momentum Conservation, that is:

`m_(A) \cdot v_(A) + m_(B) \cdot v_(B) = (m_(A) + m_(B)) \cdot v`

The final velocity of the system is:

`v = (m_(A)\cdot v_(A) + m_(B)\cdot v_(B))/(m_(A)+m_(B))`

`v=((2\,kg)\cdot(3\,(m)/(s))+(1\,kg)\cdot(-8\,(m)/(s)))/(2\,kg+1\,kg)`

`v=-0.667\,(m)/(s)`