Question

The area of a rectangular wall of a barn is 192 sq. ft. It’s length is 8 ft. longer than twice it’s width. Find the length and width of the wall of the barn?

Answer 1

width is -4+
`\sqrt{13` and it's length is 4+
`\sqrt{13`.

Explanation:

Let it's width be X. Then the area is x(x+8) = x^2+8x= 192. This is equal to
`x^2+8x - 192 = 0` . X = -4 Plus/Minus
`\sqrt{13`. Since x is positive, it's width is -4+
`\sqrt{13` and it's length is 4+
`\sqrt{13`.