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The area of a rectangular wall of a barn is 192 sq. ft. It’s length is 8 ft. longer than twice it’s width. Find the length and width of the wall of the barn?

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Answer:

width is -4+
\sqrt{13 and it's length is 4+
\sqrt{13.

Explanation:

Let it's width be X. Then the area is x(x+8) = x^2+8x= 192. This is equal to
x^2+8x - 192 = 0 . X = -4 Plus/Minus
\sqrt{13. Since x is positive, it's width is -4+
\sqrt{13 and it's length is 4+
\sqrt{13.

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