Question

A magnetic field is used to suspend a wire of mass 0.04 kg and length 0.13 m . The wire is carrying a current of 15 A . What minimum magnetic-field magnitude is needed to balance the pull of gravity

Answer 1

0.087 T

Step-by-step explanation:

Note: The weight of the mass suspended is equal the force produced by the current carrying conductor in the magnetic field and this is the force needed to balance the pull of gravity

Fm = mg = BIL................................... Equation 1

Make B the subject of the equation

B = mg/IL.................................. Equation 2

Where B = magnetic Field, m = mass, g = acceleration due to gravity, I = Current, L = Length of the wire.

Given: m = 0.04 kg, I = 15 A, L = 0.13 m,

Constant: g = 9.8 m/s²

Substitute into equation 2

B = (0.04×9.8)/(15×0.13)

B = 0.392/4.5

B = 0.087 T