Answer:
Qin = 1857 kJ
Step-by-step explanation:
Given
m = 0.5 Kg
T₁ = 25°C = (25 + 273) K = 298 K
P₁ = 100 kPa
P₂ = 500 kPa
First, the temperature when the piston starts rising is determined from the ideal gas equations at the initial state and at that state:
T₂ = T₁*P₂/P₁
⇒ T₂ = 298 K*(500 kPa/100 kPa) = 1490 K
Until the piston starts rising no work is done so the heat transfer is the change in internal energy
Qin = ΔU = m*cv*(T₂-T₁)
⇒ Qin = 0.5*3.1156*(1490 - 298) kJ = 1857 kJ