Answer:
25.1 g is the mass of chlorine in the sample
Step-by-step explanation:
P . V = n . R . T
We apply the Ideal Gases Law to solve the excersise.
We need to convert the T°C to T°K → 37°C + 273 = 310K
We replace data: 3 atm . 3L = n . 0.082 L.atm /mol.K . 310K
9 atm.L / (0.082 L.atm /mol.K . 310K) = n → 0.354 moles
We convert the moles to mass, to reach the answer
0.345 mol . 70.9g / 1mol = 25.1 g