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A population has a mean muequals71 and a standard deviation sigmaequals24. Find the mean and standard deviation of a sampling distribution of sample means with sample size nequals64.

User Eli Arbel
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1 Answer

2 votes

Answer:

Mean 71

Standard deviation 3

Explanation:

We use the Central Limit Theorem to solve this question.

The Central Limit Theorem estabilishes that, for a random variable X, with mean
\mu and standard deviation
\sigma, the sampling distribution with a large sample size can be approximated to a normal distribution with mean
\mu and standard deviation
s = (\sigma)/(√(n))

In this problem, we have that:


\mu = 71, \sigma = 24, n = 64. So

Mean 71

Standard deviation
s = (24)/(√(64)) = 3

User MDragon
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