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A car speeding down the highway honks its horn, which has a frequency 392 Hz, but a resting bystander hears the frequency 440 Hz. If the speed of sound in air is 343 m/s, how fast is the car moving

User MaddHacker
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1 Answer

3 votes

Answer:

37.42 m/s

Step-by-step explanation:

We know that apparent frequency,
\bar f is given by


\bar f=f\frac {V}{V-V_s} where f is the given frequency in this case 392, V is the speed of sound in air which is given as 343 and
V_s is the speed of car which is unknown, \bar f is given as 440 Hz


440=392* \frac {343}{343-V_s}\\343-V_s=392* \frac {343}{440}=305.5818182\\V_s=343-305.5818182=37.41818182\approx 37.42 m/s

User Ronald Blaschke
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