Question

5. The volume of a sample of helium is 4.50 L at 20.0°C and 203.0 kPa. What will its volume be

at 10.0"C and 203.0 kPa?​

Answer 1

The volume will be 2.25 L.

Step-by-step explanation:

As per Charle's law, the volume of a gaseous system is directly proportional to the temperature provided the system is at constant pressure. Since volume of gas is directly proportional to the temperature of the gas molecules, V∝ T

So, in case there is a change in temperature with constant pressure, then there will be equal change in volume.

`(V_(1))/(V_(2) ) = (T_(1))/(T_(2) )`

Thus, here
`V_(1)` = 4.50 L ,
`T_(1)`= 20 °C and
`P_(1)` =
`P_(2)` = 203 k Pa ,
`T_(2)` = 10°C.

Since, volume and temperature is directly proportional then there will be increase in volume with increase in temperature and vice versa.

`(4.50)/(V_(2) ) = (20)/(10)`

`V_(2) = (4.50*10)/(20) = 2.25 L`

So, the new volume is 2.25 L.