Question

Ammonium phosphate ((NH4)3PO4) is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid (H3PO4) with ammonia (NH3).

What mass of ammonium phosphate is produced by the reaction of 4.9 g phosphoric acid?

Answer 1

The mass of ammonium phosphate produced by the reaction of 4.9 g of phosphoric acid is 7.45 g.

Step-by-step explanation:

The question asks for the mass of ammonium phosphate produced by the reaction of 4.9 g of phosphoric acid. To determine the mass of ammonium phosphate produced, we need to balance the chemical equation and calculate the molar mass of both reactants and products.

The balanced equation for the reaction is:3H3PO4 + (NH4)OH → (NH4)3PO4 + 3H2O

The molar mass of phosphoric acid (H3PO4) is 97.99 g/mol. The molar mass of ammonium phosphate ((NH4)3PO4) is 149.0 g/mol.

Using the molar mass of phosphoric acid and the ratio of the reactants and products in the balanced equation, we can calculate the mass of ammonium phosphate produced.First, calculate the moles of phosphoric acid:

moles of H3PO4 = mass (g) / molar mass (g/mol)

moles of H3PO4 = 4.9 g / 97.99 g/mol = 0.050 moles

Since the stoichiometry of the reaction is 1:1 between phosphoric acid and ammonium phosphate, the moles of ammonium phosphate produced is also 0.050 moles.

Finally, calculate the mass of ammonium phosphate:mass of (NH4)3PO4 = moles of (NH4)3PO4 × molar mass of (NH4)3PO4

mass of (NH4)3PO4 = 0.050 moles × 149.0 g/mol = 7.45 g

Therefore, 7.45 g of ammonium phosphate is produced by the reaction of 4.9 g of phosphoric acid.

Answer 2

7.46 g

Step-by-step explanation:

Equation for the reaction can be represented as:

`3NH_3 +H_3PO_4 -----------> [{(NH_4)_3PO_4]`

1 mole of phosphoric acid is equivalent to 1 mole of ammonium phosphate in the above reaction; and as such;

numbers of moles of phosphoric acid = numbers of moles of ammonium phosphate

Given that the mass of phosphoric acid = 4.9 g; we can determine the number of moles of phosphoric acid in the process.

`number of moles = (mass)/(molarmass)`

mass = 4.9 g

molar mass = 98 g/mol

numbers of moles =
`(4.9)/(98)`

= 0.05 mole

Therefore, the mass of ammonium phosphate can be determine:

mass = number of moles × molar mass

mass of ammonium phosphate = 0.05 mole × 149.09 g/mol

mass of ammonium phosphate = 7.4545 g

mass of ammonium phosphate ≅ 7.46 g