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A farmer sold 20% of his chickens in the morning. He sold 240 chickens in the afternoon. He had 30% of his chickens left. How many chickens did the farmer have at first?

2 Answers

4 votes

Answer: the answer is C = 480

Explanation:

User Rahul Shivsharan
by
5.8k points
3 votes

Answer:

The afrmer had 480 chickens at first

Explanation:

We make an assumption here, that the initial number of chickens that the farmer has, is C.

Chickens sold by the farmer is (20% of C) + 240 chickens

Number of chickens left after selling in the morning and afternoon is 30% of C

So, the first number of chickens = Number of chickens sold + Number of chickens left

This gives us an equation that will be solved to obtain C.

C = (
(20)/(100) × C) + 240 chickens + (
(30)/(100) × C) = 0.2C + 240 chickens + 0.3C

C = 0.5C + 240 chickens

C - 0.5C = 240 chickens

0.5C = 240 chickens

C =
(240 chickens)/(0.5)

C = 480 Chickens

User Nick Brown
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6.4k points