Question

When solid (NH4)(NH2CO2)(NH4)(NH2CO2) is introduced into an evacuated flask at 25 ∘C∘C, the total pressure of gas at equilibrium is 0.116 atmatm. What is the value of KpKp at 25 ∘C∘C?

Answer 1

the value of Kp at 25°C is 2.37 × 10⁻⁴atm³

Step-by-step explanation:

Given that Kp = 0.116atm

NH₄(NH₂CO₂)(s) ⇄ 2NH₃(g) + CO₂(g)

2x atm xatm

Pt = PNH₃ PCO₂

0.116 = 2x + x

0.116 = 3x

x = 0.116/3

x = 0.039 atm

PNH₃ = 2x =2(0.039) = 0.078 atm

PCO₂ = x = 0.039 atm

Now,

KP = PNH₃² × PCO₂

= 0.078² × 0.039 atm³

= 2.37 × 10⁻⁴ atm³

the value of Kp at 25°C is 2.37 × 10⁻⁴atm³