Question

At 25 °C, an aqueous solution has an equilibrium concentration of 0.00423 0.00423 M for a generic cation, A + A+ (aq), and 0.00423 0.00423 M for a generic anion, B − B− (aq). What is the equilibrium constant, K sp Ksp , of the generic salt AB (s)

Answer 1

Answer : The value of
`K_(sp)` of the generic salt AB is,
`1.79* 10^(-5)`

Explanation : Given,

Concentration of generic cation,
`A^+` = 0.00423 M

Concentration of generic anion,
`B^-` = 0.00423 M

The equilibrium chemical reaction will be:

`AB(s)\righleftharpoons A^+(aq)+B^-(aq)`

The solubility constant expression for this reaction is:

`K_(sp)=[A^+][B^-]`

Now put all the given values in this expression, we get:

`K_(sp)=(0.00423M)* (0.00423M)`

`K_(sp)=1.79* 10^(-5)`

Thus, the value of
`K_(sp)` of the generic salt AB is,
`1.79* 10^(-5)`