Question

When the pressure that a gas exerts on a sealed container changes from 53.0 Bar to 35.2 Bar, the temperature changes from _____ C to 12.0 C. Use P1/T1=P2/T2

Answer 1

Answer: 156.1

Step-by-step explanation:

Answer 2

`156.1^(\circ)C`

Step-by-step explanation:

We can solve the problem by using Gay-Lussac's law, which states that:

"For a fixed mass of ideal gas kept at constant volume, the pressure of the gas is directly proportional to its absolute temperature"

Mathematically:

`(p)/(T)=const.`

where

p is the pressure

T is the absolute temperature

The equation can be also rewritten as

`(p_1)/(T_1)=(p_2)/(T_2)`

where, in this problem:

`p_1 = 53.0 Bar` is the initial pressure

`p_2=35.2 Bar` is the final pressure

`T_2=12.0^(\circ)+273=285 K` is the final temperature

Solving for T1, we find the initial temperature:

`T_1=(p_1 T_2)/(p_2)=((53.0)(285))/(35.2)=429.1 K`

Converted into Celsius degrees,

`T_2=429.1-273=156.1^(\circ)C`