Question

What is the daughter nucleus (nuclide) produced when 64 Cu Cu64 undergoes beta decay by emitting an electron? Replace each question mark with the appropriate integer or symbol.

Answer 1

Answer: The daughter nuclide formed by the beta decay of given isotope is
`_(30)^(64)\textrm{Zn}`

Step-by-step explanation:

Beta decay is defined as the process in which beta particle is emitted. In this process, a neutron gets converted to a proton and an electron.

The released beta particle is also known as electron.

`_Z^A\textrm{X}\rightarrow _(Z+1)^A\textrm{Y}+_(-1)^0\beta`

We are given:

Parent isotope =
`_(29)^(64)\textrm{Cu}`

The chemical equation for the beta decay process of
`_(29)^(64)\textrm{Cu}` follows:

`_(29)^(64)\textrm{Cu}\rightarrow _(30)^(64)\textrm{Zn}+_(-1)^0\beta`

Hence, the daughter nuclide formed by the beta decay of given isotope is
`_(30)^(64)\textrm{Zn}`