Question

PLEASE ANSWER ASAP!!! ITS TIMED!!

What is the equation of the line that is perpendicular to the given line and passes through the point (3, 4)? y = –One-thirdx + 5
y = –One-thirdx + 3
y = 3x + 2
y = 3x − 5

Answer 1

Answer (D) y=3x-5

Step-by-step explanation:

Answer 2

Question:

On a coordinate plane, a line goes through (negative 3, 2) and (0, 1). A point is at (3, 4). What is the equation of the line that is perpendicular to the given line and passes through the point (3, 4)? y = –One-thirdx + 5 y = –One-thirdx + 3 y = 3x + 2 y = 3x − 5

Answer:

Option D:
`y=3x-5` is the equation of the line

Step-by-step explanation:

It is given that the line passes through the points
`(-3,2)` and
`(0,1)`

We shall find the equation of the line that passes through the points
`(-3,2)` and
`(0,1)`

Slope
`m=(1-2)/(0+3)`

`m=(-1)/(3)`

Also, it is given that the line is perpendicular to the line having slope
`m=(-1)/(3)`

Since, we know that if two lines are perpendicular, then the product of the two slope is equal to -1.

Thus, we have,

`m_1\cdot m_2=-1`

`(-1)/(3) \cdot m_2=-1`

`m_2=3`

Thus, the slope of the line is
`m=3` and passes through the point
`(3,4)`

Now, we shall find the equation of the line using the formula,

`y-y_1=m(x-x_1)`

Thus, we have,

`y-4=3(x-3)`

`y-4=3x-9`

`y=3x-5`

Thus, the equation of the line is
`y=3x-5`

Hence, Option D is the correct answer.