Question

Please helpppppppppp

Answer 1

The answer is
`a=6k(k+6)`

Explanation: use Square of Sum
`(a+b)^2=a^2+2ab+b^2` and use Difference of Squares
`a^2-b^2=(a+b)(a-b)`.

`(6k^2-36k)/(a)*(k^2+12k+36)/(k^2-36) =1` factor out the common term 6k

`(6k(k-6))/(a)*(k^2+12k+36)/(k^2-36)=1\\\\(6k(k-6))/(a)*(k^2+2(k)(6)+6^2)/(k^2-36)=1` use Square of Sum then Difference of Squares

`(6k(k-6))/(a)+((k+6)^2)/((k^2-36)) =1\\\\(6k(k-6))/(a)+((k+6)^2)/((k+6)(k-6)) =1\\\\` cancel k-6 then use the rule a/b*c/d=ac/bd

`(6k)/(a)*((k+6)^2)/(k+6) =1\\\\(6k(k+6)^2)/(a(k+6)) =1\\\\(6k(k+6))/(a)=1\\\\6k(k+a)=a\\\\a=6k(k+6)`

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)

- Cutiepatutie ☺❀❤

Answer 2

A = 6k^2 + 36

Explanation:

6k^2 - 36k k^2 + 12k + 36

--------------- × -------------------- = 1

A k^2 - 36

6k ( k - 6) ( k + 6) ( k + 6)

--------------- × --------------------- = 1

A (k - 6) (k +6)

6k ( k + 6)

-------------- = 1

A

When cross multiplied:

A = 6k ( k + 6)

A = 6k^2 + 36