Question

What are all the values of x that make the inequality 8 - 3x < 20 true?

Answer 1

To solve the inequality 8 - 3x < 20, subtract 8 from both sides and divide by -3, reversing the inequality sign, to find that x > -4. Thus, all values greater than -4 satisfy the inequality.

Step-by-step explanation:

To find all values of x that make the inequality 8 - 3x < 20 true, we perform the following steps:

Divide both sides by -3, remembering to reverse the inequality sign: -3x / (-3) > 12 / (-3), which simplifies to x > -4.

Therefore, the values of x that satisfy the inequality are all real numbers greater than -4.

Answer 2

hello!

Let's solve this inequality.

First of all, subtract 8 from both sides:-

`\sf{-3x < 20-8}`

`\sf{-3x < 12}`

Divide both sides by -3:-

`\sf{x > -4}`

Notice that the inequality sign changed...

Here's the rule:-

When you multiply/divide both sides by a negative number, you flip the inequality sign; so if we have "less than" it becomes "greater than" and so on...

So these are the values of x that will make the inequality true:-

`\bigstar{\boxed{\pmb{The~numbers~greater~than~-4}}}`

Well, -3 is greater than 4 :)

Let's plug it in and see if it makes the inequality true:-

-3>-4

Yes, it does make the inequality true :)

note:-

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)