Slope of the line is
.
x-intercept is 0 and the y-intercept is 0.
direct variation equation relating x and y is
.
Solution:
Let the points on the line are (–3, 2) and (3, –2).
![x_1=-3, y_1=2, x_2=3, y_2=-2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/beh9x7j4dan5c3oqwipkb9ur3vgvk2ivl1.png)
Slope of the line:
![$m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ej5dbt33a3msr0t53n100ov7xd8u2xicjg.png)
![$m=(-2-2)/(3-(-3))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/iw73hqycjyf98r7zr6feqp0tbc47xasauw.png)
![$m=(-4)/(3+3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/skp8slaqmts0wjv7gqpd9qyoh7phkwb7ey.png)
![$m=(-4)/(6)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/24fuzhw1yqefme0uv0axkgqenwjvfwc552.png)
![$m=(-2)/(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ox1zgg65nc7gkidxgizq44i2pzhrb83zbp.png)
Slope of the line is
.
The x-intercept is, where a line crosses at x-axis.
The y-intercept is, where a line crosses at y-axis.
Here, x-intercept is 0 and the y-intercept is 0.
Direct variation form:
y = mx
![y=(-2)/(3)x](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3wpyxl6a4lkzpx49lq4gl4482lcom2stl7.png)
Hence slope of the line is
.
x-intercept is 0 and the y-intercept is 0.
direct variation equation relating x and y is
.