Question

A farmer is using a rope and pulley to lift a bucket of water from the bottom of a well. The farmer uses a force F1 = 54.5 N to pull the bucket of water upwards at a constant speed. The bucket, when empty, has a mass of mb = 1.1 kg.

Answer 1

(a) Mass of the water in the bucket is
`4.46\ kg`.

(b) The volume of water will be
`4460\ cm^3`

Step-by-step explanation:

The question is incomplete the complete question is given below.

A farmer is using a rope and pulley to lift a bucket of water from the bottom of a well. The farmer uses a force
`F_1 = 54.5\ N` to pull the bucket of water upwards at a constant speed. The bucket, when empty, has a mass of
`(m_b)` = 1.1 kg.

(a) Calculate the mass of the water in the bucket,
`(m_w)` in kg

(b) Calculate the volume of the water in the bucket,
`V_w` in
`cm^3`. Use density of the water 1.00 g/

Given the farmer uses a force
`F_1 = 54.5\ N` to pull out the bucket.

Also, the mass of the bucket
`(m_b)` is
`1.1\ kg`

The force due to mass of bucket
`(m_b)` and mass of water
`(m_w)` will balance the force used by farmer.

So,

`F_1=(m_b+m_w)g`

`54.5=(1.1+m_w)* 9.81\\(54.5)/(9.81)=(1.1+m_w)\\5.56=(1.1+m_w)\\m_w=5.56-1.1\\m_w=4.46\ kg`

So, mass of the water in the bucket is 4.46 kg.

Now, let us work on next part.

Given density of the water
`\rho_w=1\ g/cm^3`

`\rho_w=(m_w)/(V_w)\\V_w=(m_w)/(\rho_w)`

`m_w=4.46\ kg=4.46*1000\ g=4460\ g`

`V_w=(4460)/(1)=4460\ cm^3`

So, the volume of water will be
`4460\ cm^3`