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(sina + cosa +1)/(sina+cosa-1)- (1+sina-cosa)/(1-sina+cosa)=2(1+coseca)​
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(sina + cosa +1)/(sina+cosa-1)- (1+sina-cosa)/(1-sina+cosa)=2(1+coseca)​

User IOIIOOIO
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6 votes

I solve this question with further steps which was not so much necessary, but it's correct

(sina + cosa +1)/(sina+cosa-1)- (1+sina-cosa)/(1-sina+cosa)=2(1+coseca)​-example-1
(sina + cosa +1)/(sina+cosa-1)- (1+sina-cosa)/(1-sina+cosa)=2(1+coseca)​-example-2
User Ocos
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