106k views
2 votes
(sina + cosa +1)/(sina+cosa-1)- (1+sina-cosa)/(1-sina+cosa)=2(1+coseca)​

User IOIIOOIO
by
7.1k points

1 Answer

6 votes

I solve this question with further steps which was not so much necessary, but it's correct

(sina + cosa +1)/(sina+cosa-1)- (1+sina-cosa)/(1-sina+cosa)=2(1+coseca)​-example-1
(sina + cosa +1)/(sina+cosa-1)- (1+sina-cosa)/(1-sina+cosa)=2(1+coseca)​-example-2
User Ocos
by
6.4k points