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Assume we perform a known-plaintext attack against DES with one pair of plaintext and ciphertext. How many keys do we have to test in a worst-case scenario if we apply an exhaustive key search in a straightforward way? How many on average?

1 Answer

6 votes

Answer:


2^(55) keys in a worst case scenario

Step-by-step explanation:

So, Average will be :
2^(56) /2


2^(55)(Answer)

User Karthik Kolanji
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