Answer:
the claim is false
Step-by-step explanation:
Power consumed = mgh
m = ρv where volume per seconds ( 1 l = 0.001 m³) = 50 L/s × 0.001 m³ = 0.05 m³, ρ density of water = 1000 kg/m³
P consumed = ρv gh = 0.05 m³×1000 kg/m³ × 9.8m/s × 30 m = 14700 = 14.7 Kw
This claim is false because the power consumed is greater then the 2kW reported.